A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. It takes a time of 2.90 s for the boat to travel from its highest point to its lowest, a total distance of 0.700 m . The fisherman sees that the wave crests are spaced a horizontal distance of 5.50 m apart.

wavelength   = 5.50 m

The period T = 5.80 s

The speed v = 0.948 m/s

Amplitude A of each wave  = 0.350 m

Explanation:

Since the wave crests is 5.50 m; then we can say that the distance from one peak to another is equal to a single wavelength;

SO; wavelength   = 5.50 m

Given that ; the time to travel from the highest point to the lowest point = 2.90 s

Thus ; which implies just only about half of one wavelength

The period  for one wavelength T = twice of half of one wavelength which can be expressed as :

T =

T = 2 (2.90 s)

T = 5.80 s

The speed of the wave can be determined via the formula;

The amplitude A is half the distance because the distance illustrates the peak to peak vertical displacement of the wave ;

∴

A =

A = 0.350 m

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)