A tire swing is released from some initial height such that the speed of the tire at the
bottom of the swing is 2.5 m/s. What is the initial height of the tire? Note: g = 9.8 m/s2
A 0.13m
B 0.16m
C 0.32m
D 3.1 m

The Initial height of the tire will be 0.32 m

Explanation:

We  have the formula,

h=Vf^2/2g

h=V×f×f/2g

where Vf denotes the speed of the tire at the bottom of the swing

where g denotes the acceleration

due to the gravity

h=2.5×2.5=6.25

2×9.8 =19.8

h=6.25/19.8

h=0.32

The Initial height of the tire will be 0.32 m

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