A car driving at an initial velocity of 7.5 m/s accelerates at a rate of 2.0 m/s2 for 2.5
seconds. What distance does the car travel during this time period?
A.14 m
B.21 m
C.25 m
D.31 m

Correct  C.  D = 25 m

Explanation:

Given:

V₀ = 7.5 m/s  Initial velocity

a = 2 m/s²   acceleration

t = 2.5 seconds  the time interval for which the distance traveled is required

According to the data provided, we have seen that the subject is a uniformly accelerated motion to which the formula applies:

D = V₀ · t + (a · t₂²)/2

D = 7.5 · 2.5 + (2 · 2.5²) / 2 = 18.75 + 6.25 = 25 m

D = 25 m

God is with you!!!

gravity

explanation:

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .