A gas-filled weather balloon has a volume of 53.0 l at ground level, where the pressure is 751 mmhg and the temperature is 25.0 °c. after being released, the balloon rises to an altitude where the temperature is –2.01 °c and the pressure is 0.511 atm. what is the weather balloon's volume at the higher altitude?

Explanation:

We shall apply gas law formula

P₁V₁ / T₁ = P₂V₂/T₂

P₁ , V₁ ,  T₁ are initial pressure , volume and temperature and  P₂ , V₂, T₂ are final pressure , volume and temperature of the gas

P₁ = 751 mmHg , P₂ = .511 x 760 mmHg = 388.36 mmHg

T₁ = 273 + 25 = 298K , T₂ = 273 - 2.01 = 270.93 K

V₁ = 53 L , P₂ = ?

Putting the given values in the equation

751 x 53 / (273 +25) =  388.36 x V₂ / 270.93

V₂ = 93.18 L .

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation: