As a particle moves along an x axis, a force in the positive direction of the axis acts on it. The plot shows the magnitude F of the force versus position x of the particle. The curve is given by F = a/x2, with a = 9.0 N·m2. Find the work done on the particle by the force as the particle moves from x = 1.0 m to x = 3.0 m by integrating the force function.

The work done on the particle is 6 J

Explanation:

The work done on the particle is equal to:

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14