Force during a jump.
an average person can reach a maximum height of about 60 cm when jumping straight up. during the jump itself, the person’s body from the knees up typically rises a distance of around 50 cm.
(a) with what initial speed does the person leave the ground to reach a height of 60 cm?
v(final) = v(initial) +2a(delta{y})
0 =v(initial) + 2(-9.8m/)
v(initial) = 3.4 m/s
(c) in terms of this jumper’s weight w, what
force does the ground exert on him or her during the jump?
v(final) = v(initial) +2a(delta{y})
(3.4m/s)^ = 0 + 2a(.05m)
a = 11.6 m/s^2
n-w = ma
n = w( 1 + a/g)
n = w( 1 + 11.6m/s^2/9.8m/s^2)
n=2.2w