What is the acceleration of the car at segment C?

30 m/s2
–30 m/s2
40 m/s2
–40 m/s2

-30 m/s²

Explanation:

Given that,

Initial velocity at C (Vi) = 40 m/s

Final velocity at D Vf = 10 m/s

acceleration A = ?

Time taken T = Time at the end of segment C - Time at the start of segment C

(6s - 5s) = 1s

Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (Vf - Vi)/T

A = (10 m/s - 40 m/s) / 1s

A = -30 m/s / 1s

A = -30 m/s² (negative acceleration means the car slowed down at segment C)

Thus, the acceleration of the car at segment C is -30 m/s²

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle