Assuming that the smallest measurable wavelength in an experiment is 0.950 fm , what is the maximum mass of an object traveling at 241 m ⋅ s − 1 for which the de Broglie wavelength is observable?

The maximum mass is

Explanation:

The wavelength of the electron can be determined by means of the De Broglie equation.

(1)

Where h is the Planck's constant and p is the momentum.

 (2)

Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

--

Finally, equation 2 can be used.

But

Hence, the maximum mass is

0.0289 x 10⁻¹⁹kg

The de Broglie wavelength, λ, of a particle varies inversely with the momentum (the product of the mass, m, and velocity, v) of the particle. i.e

λ ∝

λ =            ------------------------(i)

Where;

h = constant of proportionality called Planck's constant = 6.626 x 10⁻³⁴Js

From the question;

λ = 0.950fm = 0.950 x 10⁻¹⁵m

v = 241ms⁻¹

Substitute these values into equation (i) as follows;

0.950 x 10⁻¹⁵ =

Solve for m;

m =

m = 0.0289 x 10⁻¹⁹kg

Therefore, the maximum mass of the object is 0.0289 x 10⁻¹⁹kg

d) physical means can be used to separate the components of air.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.