A particle is located on the x axis at x = 2.0 m from the origin. A force of 25 N, directed 30° above the x axis in the x-y plane, acts on the particle. What is the torque about the origin on the particle?

25 Nm

Explanation:

Parameters given

Distance of the particle from the origin, r = 2.0 m

Force acting on particle, F = 25 N

Angle of force, θ = 30°

The torque acting on a particle is given as:

τ = r * F * sinθ

Where r = radius of axis of rotation. This is the same as the position of the particle on the x axis.

Therefore, the torque will be:

τ = 2 * 25 * sin30

τ = 25 Nm

The torque acting on the particle is 25 Nm.

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