A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. The ball is in contact with the wall for t = 0.066 s.

1)

What is the magnitude of the initial momentum of the racquet ball?

kg-m/s

2)

What is the magnitude of the change in momentum of the racquet ball?

kg-m/s

3)

What is the magnitude of the average force the wall exerts on the racquet ball?

Explanation:

Given that,

Mass of the, m = 0.256 kg

Initial peed of the ball, v = 11.8 m/s

The ball is in contact with the wall for t = 0.066 s

(1) The magnitude of the initial momentum of the racquet ball is given by :

p = mv

(2) It is projected at angle of 29 degrees. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal.

The change in momentum of the racquet ball is given by :

(3) Impulse is equal to the change in momentum.

Hence, this is the required solution.

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation: