A circular loop of radius 0.10 m is rotating in a uniform external magnetic field of 0.20 T. Find the magnetic flux through the loop due to the external field when the plane of the loop and the magnetic field vector are parellel.

The magnetic flux through the loop is 0.006284 m².T

Explanation:

Given;

radius of circular loop, r = 0.1 m

magnetic field strength, B = 0.2 T

Magnetic flux through the loop due to the external field is given as;

Φ = BAcosθ

where;

Φ is magnetic flux

B is the magnetic field strength

A is the area of the loop

θ is the angle of inclination of between the plane of the loop and external magnetic field

A = πr² = π(0.1)² = 0.03142 m²

θ = 0, since they are parallel

Φ = BAcosθ

Φ = 0.2 x 0.03142 x cos0

Φ = 0.006284 m².T

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