4. A ball of clay, of mass m, traveling at speed vo, collides and sticks to a stationary stick. The ball approaches the stick in a direction perpendicular to the length, striking the stick at a distance D from the CM of the stick. The stick + ball system then moves, rotating about a new center of mass, CM’.
1. Where is the new CM' relative to the CM 'of the stick?
2.What is the final speed of the new CM'?
3. What is the final angular velocity of the sustem about the new CM'?

1) X' = mD/(M + m)

2)

3)

Explanation:

1)  mass of stick  = M

mass of clay = m

Location of original center of mass of stick, =  0 (at the origin)

Location of center of mass of clay, = D

X' = location of center of mass of the stick + ball system

The equation below applies for center of mass

X'(M+m) =

But and

X'(M+m) = M (0) + m (D)

X' = mD/(M + m)

2)  Let = speed of the clay ball before collision

speed of the stationary stick before collision = 0 m/s

V = speed of the stick-ball system after collision

Applying the principle of momentum conservation

3)

I = moment of inertia of the stick about the center of mass of the system  

Using conservation of angular momentum

But X' = mD/(M + m)

answer: he got 23

explanation:

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me