A soccer ball is kicked horizontally off a bridge with a height of 36m. The ball travels 25m horizontally before it hits the pavement below. What was the soccer ball's speed when it was first kicked?

9.22 m/s

Explanation:

Vertical height, y = 36 m

Horizontal distance, d = 25 m

Let the initial velocity of projection is u and it is projected horizontally.

Let t be the time taken by the ball to hit the ground.

For horizontal motion

horizontal distance = horizontal velocity x time

d = u x t

25 = u x t (1)

Use second equation of motion for vertical direction

y = 0.5 x g t², as the initial vertical velocity is zero.

36 = 0.5 x 9.8 x t²

t = 2.7 second

Put in equation (1)

25 = u x 2.7

u = 9.22 m/s

Thus, the initial velocity with which the ball is projected horizontally is 9.22 m/s.

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over