A graduated cylinder measures 17.1 mL of water. A small shiny gold piece of metal is gently dropped into the graduated cylinder and the water displaces to 19.8 mL. What is the volume of the piece of gold?

2.7mL

Explanation:

From the question given, we obtained the following:

Volume of water = 17.1 mL

Volume of water + gold = 19.8mL

From Archimedes' principle, we understood that an object will displace its own volume from a liquid when immersed in the liquid. With this understanding, we can obtain the volume of the gold as follow:

Volume of water + gold = 19.8mL

17.1 mL + gold = 19.8mL

Collect like terms

gold = 19.8mL - 17.1mL

gold = 2.7mL

Therefore, the volume of gold is 2.7mL

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.