A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T then bends the ion into a circular path of radius 0.305 m. What is the mass of the ion?

The mass of the ion is 5.96 X 10⁻²⁵ kg

Explanation:

The electrical energy given to the ion Vq will be changed into kinetic energy

As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force .

So,

and

Right from these eliminating v, we can derive

On substituting the value, we get:

m = 5.96 X 10⁻²⁵ kg.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.