A charge is accelerated from rest through a potential difference V and then enters a uniform magnetic field oriented perpendicular to its path. The field deflects the particle into a circular arc of radius R. If the accelerating potential is tripled to 3 V, what will be the radius of the circular arc?
Motion of a charged particle in an electric field and in a magnetic field:
When a charged particle moves between two point in an electric field, having a potential difference V, the change in the energy of the particle is given by:
ΔE=qV
Also, when a charged particle moves through a region of magnetic field with its velocity perpendicular to the magnetic field it experiences a force given by:
F=qvB
where:
q is the charge of the particle
v is the speed of the particle
B is the strength of the magnetic field

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the closer the planet is to the sun, the larger the gravity

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.