A 2000kg car traveling 30m/s slams on their brakes to stop. Maximum braking force of the car is 20,000 Newton's, how far does the car travel from the time they slam on their brakes till it stops?

45 m

Explanation:

From the question,

The kinetic Energy of the car = Work done by the brake that is  needed to stop the car.

1/2mv² = F×d Equation 1

Where m = mass of the car, v = velocity of the car, F = braking force of the car, d = distance the car travels before it comes to rest.

make d the subject of the equation

d = 1/2mv²/F Equation 2

Given: m = 2000 kg, v = 30 m/s, F = 20000 N

Substitute into equation 2

d = 1/2(2000)(30²)/20000

d = 1000(30²)/20000

d = 900000/20000

d = 45 m.

Hence the car travels 45 m before it comes to rest

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

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1.            c. is smaller

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