500mL of He at 98 kPa expands to 750 mL. Find P2

The value of P₂ is 65.33 kPa

Explanation:

Given:

Volume, V₁ = 500mL

Pressure, P₁ = 98 kPa

Volume, V₂ = 750 mL

Pressure, P₂ = ?

According to Boyle's law:

P₁V₁ = P₂V₂

On substituting the value we get:

The value of P₂ is 65.33 kPa

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

hypothesising or postulating