If a metal wire carries a current of 0.10 A, how long does it take for 5.00x1018 electrons to pass a given cross-
sectional area of the wire? (The charge on one electron is 1.6x10-19 C.)

8 seconds

Explanation:

The current in a wire is defined as

where

q is the charge passing through a given point of the wire in a time t

In a metal wire, the current is generally carried by electrons. So, the charge passing through a certain point of the wire can be written as

where

N is the number of electrons

is the fundamental charge (the charge of one electron)

So the formula becomes

In this metal wire we have

I = 0.10 A is the current in the wire

is the number of electrons

Solving for the time, we find:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .