The force needed to lift an object is equal in size to the gravitational force on the object. How much work is done in lifting an object that has a mass of 5 kg a vertical distance of 2 m?

Work done in lifting the object = 98 J

Explanation:

Work: Work can be defined as the product of force and distance.

The S.I unit of work is Joules (J).

Mathematically it can be expressed as

W = F × d Equation 1

Where W = work done, F = force needed to lift the object, d = distance

The gravitational force on the object = Weight of the object

Weight of the object = mg Equation 2

Where m = mass of the object, g = acceleration due to gravity

Given: m = 5 kg,

Constant: g = 9.8 m/s²

Substituting these values into equation 2

Weight of the object = 5 × 9.8

Weight of the object = 49 N

Since weight of the object = force needed to lift the object,

F = 49 N

Also Given: d = 2 m

Substituting these values into equation 1

W = 49 × 2

W = 98 J

Work done in lifting the object = 98 J

hope this helps

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  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

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