Suppose a van de Graaff generator builds a negative static charge, and a grounded conductor is placed near enough to it so that a 7.0 x 10-6 coulombs of negative charge arcs to the conductor. Calculate the number of electrons that are transferred.

Given Information:

Charge = q = 7.0x10⁻⁶ C

Required Information:

Number of electrons = n = ?

Number of electrons = 4.375x10¹³

Explanation:

We know that charge is given by

q = n*e

Where n is the number of electrons and e is the electronic charge that is 1.60x10⁻¹⁹ C

n = q/e

n = 7.0x10⁻⁶/1.60x10⁻¹⁹

n = 4.375x10¹³ electrons

Therefore, 4.375x10¹³ electrons were transferred.

Number of electrons transferred = 4.375 x 10^(13)

Explanation:

From coulombs law,

Mathematically, we can say that a charge is the number of electrons multiplied by the charge on 1 electron. Symbolically, it is given as;

Q = ne

where;

q is the symbol used to represent charge

n is a number of electrons;

e is a charge on 1 electron (1.6 × 10^(-19)C).

From the question,

Q = 7.0 x 10^(-6) coulombs of negative charge

Thus, making n the subject of the formula ;

n = Q/e = 7.0 x 10^(-6)/(1.6 × 10^(-19)) = 4.375 x 10^(13)

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

the answer to this is proletariats.

hope this : )