Light of wavelength 550 nm comes into a thin slit and produces a diffraction pattern on a board 8.0 m away. The first minimum dark fringe appears 3 mm from the central maximum. What is the width of the slit?

Width of the slit will be equal to 1.47 mm

Explanation:

We have given wavelength of the light

Distance D = 8 m

Distance between first minimum dark fringe and the central maximum is 2 mm

So

We have to find the width of the slit

For the first order wavelength is equal to , here a width of slit

So

So width of the slit will be equal to 1.47 mm

less than one you can't create energy