Two particles that have the same mass m = 500 g are connected by a massless cord of � = 30 cm and rotate around O with angular speed ω = 2.0 rev/s. What is the angular momentum of the system?

The angular momentum of the system is 0.18kgm²/s

Explanation:

L = angular momentum of the particle 1 + angular momentum of the particle 2

L = ml²ω + ml²ω

L = 2ml²ω

Given that,

m = 500g are connected by a massless cord

   =0.500kg

l = 30cm

 = 0.30m

angular speed ω = 2.0 rev/s

angular momentum of the system =

L = 2ml²ω

L = 2 × 0.500 × (0.30)² × 2

L = 2 × 0.500 × 0.09 × 2

L = 0.18kgm²/s

Thus, the angular momentum of the system is 0.18kgm²/s

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

we need to know the time interval during which the force acts. impulse of force = momentum change