Two long parallel wires carry currents of 3.05 A 3.05 A and 6.69 A 6.69 A . The magnitude of the force per unit length acting on each wire is 7.33 × 10 − 5 N / m 7.33×10−5 N/m . Find the separation distance d d of the wires expressed in millimeters.

The separation between wires is 55.6 mm.

Explanation:

Given that,

Current in wire 1,

Current in wire 2,

The magnitude of the force per unit length acting on each wire is,

We know that the formula of magnitude of the force per unit length is given by :

Here, d is the separation between wires.

So, the separation between wires is 55.6 mm.

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explanation:

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