A hydraulic system is used to lift a 2100 kg (20,600 N) vehicle in a auto repair shop which is sitting on a piston with a cross-sectional area of 0.56 cm2. What is the minimum force that must be applied to the attached piston of area 0.035 cm2 in order to lift the vehicle?

1287.5 N

Explanation:

We are given that

Mass of vehicle ,m=2100 kg

Weight of vehicle ,F=20,600 N

Area,A=

We have to find the minimum force that must be applied to the attached piston of area in order to lift the vehicle.

Apply the pascal's law

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the ima (higher than 1m) will be greater than the ima with the height of 1m.