If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? It doubles. It becomes 2 times as large. It becomes half as large. It becomes 1/ 2 times as large. It remains the same.

The new frequency will increase by a factor of .

Explanation:

The frequency of a simple pendulum is given by the formula as follows :

Here,

l is the length of the simple pendulum

g is acceleration due to gravity on which the pendulum is kept

The frequency of simple pendulum is independent of its amplitude. If a simple pendulum oscillates with small amplitude and its length is doubled, l' = 2l

So, the new frequency will increase by a factor of . Hence, this is the required solution.

b would be the answer

seeing the graph would