A uniform bar has two small balls glued to its ends. The bar has length L and mass M, while the balls each have mass m and can be treated as point masses. What is the moment of inertia of this bar about an axis perpendicular to the bar through its center?

Explanation:

Length of bar = L

mass of bar = M

mass of each ball = m

Moment of inertia of the bar about its centre perpendicular to its plane is

Moment of inertia of the two small balls about the centre of the bar perpendicular to its plane is

Total moment of inertia of the system about the centre of the bar perpendicular to its plane is

I = I1 + I2

the answer is 3.1 his answer is wrong mines is right

c. magnitude and direction