An electron is trapped between two large parallel charged plates of a capacitive system. The plates are separated by a distance of 1 cm, and there is a vacuum in the region between the plates. The electron is initially found midway between the plates with a kinetic energy of 10 eV and with its velocity directed toward the negative plate. How far towards the negative plate will the electron get if the potential difference between the plates is 100 V? (1 eV = 1.602 x 10-19 J)

0.4 cm

Explanation:

We are given that

Kinetic energy=K.E=qV=10 eV

Distance between plates,d=1 cm=

1 m=100 cm

Potential difference,V=100 V

We have to find the distance of electron from negative plate.

Mass of electron=

Speed,

Electric field=

Charge on electron,q=

Acceleration,a

Final velocity,v'=0

Using the formula

1 m=100 cm

Mid of separation=

Distance of electron from negative plate=0.5-0.1=0.4 cm

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.