An electron that has a velocity with x component 2.6 × 106 m/s and y component 2.4 × 106 m/s moves through a uniform magnetic field with x component 0.029 T and y component -0.14 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.

Answer with Explanation:

We are given that

a.We have to find the magnitude of the magnetic force on the electron.

Charge on an electron,q=

Force act along positive z- direction.

b.Charge on proton=

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.