Calculate the absolute value of the magnitude of the impact force on a 60 kg parachutist falling at 10 m/s if the time to stop was 0.7 seconds.

85.7 N

Explanation:

According to Newton's second law of motion, F is equivalent to the product of mass and acceleration, ma where m is the mass of parachute in kilograms and a is acceleration.

Acceleration is defined as the rate of change of velocity per unit time hence expressed as

Where v and u represent the final and initial velocities respectively.

Substituting this into initial equation of f then

For this case, the final velocity is zero since it comes ro rest. Substituting 0 m/s dor v and 10 m/s for u then 0.7 s for t we can deduce that

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