The runner had an initial vertical velocity of -0.7 m/s and an initial horizontal velocity of 3.6 m/s. If the forces were applied over a period of 0.2 seconds, what are the runner's final vertical and horizontal velocities?

1.26m/s; 4.96m/s

Explanation

Acceleration is defined as the change I'm velocity of an object with respect to time.

Mathematically,

Acceleration (a) = change in velocity (v-u)/time (t)

Where v is the final velocity

u is the initial velocity

From the equation, it can be deduced that;

v = u+at

If the runner had an initial vertical velocity of -0.7 m/s over a period of 0.2seconds, its final velocity;

v = (-0.7)+9.81(0.2) (a=g=9.81m/s²)

v = -0.7+1.962

v = 1.26m/s

If the runner had an initial horizontal velocity of 3 m/s over a period of 0.2seconds, its final velocity;

v = 3+9.81(0.2)

v = 3+1.962

v = 4.96m/s

the answer is a 3.8cm

explanation:

its c i just checked it