Calculate the jul(i)an heat released in 20s on the resistors R1 = 6 ohm and R2 = 3 ohm which are connected in parallel, if the voltage at the ends of the resistor is U = 24V ?

The heat released in 20s is 5760J

Explanation:

Given:

Time, t = 20s

Resistor, R₁ = 6Ω

               R₂ = 3Ω

Voltage, V = 24V

Heat, H = ?

When the two resistors are connected in parallel, the net resistance would be:

Substituting the value in the above formula we get:

The net resistance is 2Ω

According to the joule's law:

On substituting the value we get:

Therefore, heat released in 20s is 5760J

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f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow