Suppose two point charges, Q1 = +3.37 x 10-6 C and Q2 = -8.21 x 10-6 C, are separated by a distance d = 1.99 m. Using Coulomb's Law, find the attractive force between the charges. A) F = 0.0626 N B) F = 0.0313 N C) F = -0.0626 N D) F = -0.0313 N
Ps If you could explain how you got it it would help a lot. Thank you so much.

No bc a lot of things r still theories n unproven

Are there options for this?

Letter a, because when there are unlike charges they will always attract to each other.

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero.