What is the current in a circuit with a 12.0 V battery and a 4.0 Ω resistor? 0.3 A 3.0 A 8.0 A

3 amperes

Explanation:

V = IR

Where

V = voltage

I = current and

R = resistor

Given

V = 12.0v

R = 4.0 ohms

Therefore

12.0 = I x 4.0

Divide both sides by 4.0

12.0/4.0 = I x 4.0/4.0

3 = I

I = 3 amperes

what type of charge does it have? negative

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