If a 60.1 kg person jumps onto a seesaw at an angle of 22 degrees at a distance of 6.9 m from the fulcrum.
How much force will their friend feel if they are sitting 6.6 m on the opposite side of the seesaw?

On the opposite side of the seesaw, the friend will feel a force of 231.66 N

Explanation:

R₁F(input)sin∅ = R₂F(output)

F(output) = R₁F(input)sin∅ / R₂

              = (6.9/6.6) (60.1 * 9.8) Sin 22°

              = 1.05 (588.98) Sin22°

              = 1.05 * 588.98 * 0.3746

F(output) = 231.66 N

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.