What is the strength of the electric field 0.1 above the center of the top surface of the plate?

7.38 x 10^3 N/c

Explanation:

The Radius of the Copper Field

R= 10.0cm

The distance of the point from the centre of the plate is

Z = 0.1mm

It shows that Z << R

We can assume that the copper plate is a large uniformly charged disk.

Therefore,

E = σ/2Eo

But,

σ = Q/A

σ = -4.1 x 10^-1 / 3.14 x (0.1)^2

σ = -1.306 x 10^-7 c/m^2

Therefore

E = 1.306 x 10^-7 / 2x 8.85 x 10^-12

E = 7.38 x 10^ 3 N/c

there are no atoms