If a person can comfortably carry 20 kg (44 lbs) and gold has a density of 19.6 g/cm3, what is the volume of the largest piece of solid gold a person can carry

1.02×10⁻³ m³

Explanation:

Density = mass/volume.

D = m/Vequation 1

Make V the subject of the equation

V = m/D Equation 2

Where V = Volume of the largest piece of solid gold a person can carry, D = Density of the Gold, m = mass a person can comfortably carry.

Given: m = 20 kg, D = 19.6 g/cm³ = 19.6(1000000/1000) kg/m³ = 19600 kg/m³

Substitute into equation 2

V = 20/19600

V = 1.02×10⁻³ m³

Hence the volume of the largest piece of solid gold a person can carry = 1.02×10⁻³ m³

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation:

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.