A force is dependent on position and is given by (4.00 N/m) x +(2.0 N/m 2) xy . An object begins at the origin. It first moves in a straight line to x = 1.00 m, y = 0.00 m. It then moves in a straight line to x = 1.00 m, y = 1.00 m. How much work is done on the object by the force during the motion described?

Explanation:

Given:

expression of force:

initial position of the object,

position after the first move,

final position after the last move,

As we know that work is defined when the force is applied and the body moves in the direction of force.

The total displacement of the object:

Now the force from initial point to the final point in the direction of displacement :

Now work done:

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grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered