A proposed space station consists of a circular tube that will rotate about its center (like a tubular bicycle tire). The circle formed by the tube has a diameter of 1.1 km. What must be the rotation speed (revolutions per day) in an effect nearly equal to gravity at the surface of the Earth (say, .90 g) is to be felt

1736rev/day

Explanation:

v = Velocity

d = Diameter = 1.1 km

r = Radius = 1.1km/2 =0.55 km = 0.55 × 10^3 m

g = Acceleration due to gravity = 9.81 m/s²

g = 0.9 g

Now use the centripetal force equation

F = mg

But to balance the gravitational force

F = mv²/r plug in this for F

Then we have ...

mv²/r = m0.9g

Solve for v , we then have

v = √0.9gmr/m

v = √0.9gr

v = √ 0.9 × 9.81 × 0.55 × 10^3

v = 69.68465m/s

We now use the equation for frequency of a period

f = v/2 π r

f = 69.68465m/s / 2 × π0.55 × 10^3

f = 0.0201 rev/seconds

Therefore revolution for a day will be

0.0201 × 24hrs × 3600

f = 1736rev/day

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.