10. A car approaching a stationary observer emits 570 Hz from its horn. If the observer detects a frequency
of 590 Hz, how fast is the car moving? The speed of sound is 343 m/s.

The speed of the car is 12 m/s.

Explanation:

As in the present problem, the frequency emitted by the source (f) is given as 570 Hz and the Doppler frequency or the frequency heard by the observer (f') is given as 590 Hz. So there is an increase in the frequency which confirms that the car is moving towards the observer. Then, the speed of the car can be obtained by substituting the known parameters in the Doppler shift frequency formula.

As the observer is stationary, the speed of observer is zero, so the numerator will only have the speed of sound which is 343 m/s. And as the car is coming towards the observer, the speed of car should be subtracted from the speed of sound in the denominator.

So, the speed of the car is 12 m/s.

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.