A 9 volt battery is hooked up to two resistors in series. one has a resistence of 5 ohms, and the other has a resistance of 10 ohms. several locations along the circuit are marked with lettersA) The current at A is greater than the current at B, which is greater than the current at C, which is greater than the current at D. B) The current at A is greater than the current at B, which is equal to the current at C, which is greater than the current at D. C) The current at A is equal to the current at B, which is equal to the current at C, which is equal to the current at D.

the answer is The current at A is equal to the current at B, which is equal to the current at C, which is equal to the current at D.

Explanation:

The 9 volt battery is connected to the two resistors 5 ohms and 10 ohms in series.

We have to know that In series connection the same current flows through out the circuit as being described from Ohms Law (V=IR)

Therefore the current at point A is equal to the current at point B and also equal to the current at point C respectively.

Each resistor in a series circuit has the same amount of current flowing through it. The voltage drop across each individual resistor in a series is different, and their combined power total adds up to the power source input.

i'm on my way to history not a mistory.

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