A hollow aluminum shaft with an outside diameter of 80 mm and a wall thickness of 4 mm has an allowable shear stress of 80 MPa. Determine the maximum torque T that may be applied to the shaft.

The value of maximum torque applied on the shaft   = 2764.4 N - mm

Explanation:

Outside diameter D = 80 mm

Thickness = 4 mm

Inside diameter d = 80 -2 × 4 = 72 mm

Allowable shear stress Z = 80 M Pa

Now the value of maximum torque is given by

Put all the values in above formula we get

⇒ =   ×

⇒ = 2764.4 N - mm

This is the value of maximum torque applied on the shaft.

answer; (arch); good luck

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2