What is the potential difference between the plates of a 4.6-F capacitor that stores sufficient energy to operate a 75.0-W light bulb for one minute?
How do i get the answer to be 44.2 V?

V = 44.2 V

Explanation:

We have time = 1 minute = 60 sec, C = 4.6 F, P = 75.0 W

Solution:

Electric Potential Energy U Formula in capacitor for the given data.

U = 1/2 CV²

V =

So to find energy U = Pt = 75.0 W × 60 sec

U = 4500 J

now V =

V = 44.232 = 44.2 V

what was the answer?

it takes about 30 days for it to break down