If the snowball takes 0.65 seconds to reach the smokestack, what is its velocity?
15 m
Smokestack
Knoll
* 4.5 m
Level ground
9.8 m/s
17 m/s
23 m/s
O 6.9 m/s

Question

What is the horizontal component of velocity at the instant the ball is thrown?

23 m/s

Explanation:

Velocity is given by diatance per unit time. In this case, the horizontal distance is 15 m and time is given as 0.65 s hence substituting the above figures for velocity, we obtain that v=23/0.65=23.076923076923 m/s

Rounded off, the horizontal velocity component is approximately 23 m/s

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