A spring has a period of 1 s when a 0.200 kg mass hung from the end of it. If the mass at the end is changed to 0.100 kg, will the period change?

When the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

Explanation:

Given-

Mass, m1 = 0.2kg

Time period, T1 = 1s

m2 = 0.1 kg

T2 = ?

We know,

where,

T = Time period

m = mass

k = spring constant

From the equation, we can see that T is directly proportion to the square root of mass, m

T ∝ √m

So,

If m1 = 0.2kg , T1 = 1s and m2 = 0.1kg

The T2 would be:

Therefore, when the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.