A 4.0-μF capacitor that is initially uncharged is connected in series with a 4.0-kΩ resistor and an ideal 17.0-V battery. How much energy is stored in the capacitor 17 ms after the battery has been connected?

2.473x10^-4J

Explanation:

C=(4x10^-6)farads, R=4000omhs, Vinital=17v, t=.017s

Use these equations τ=RC, Vfinial=Vinital(1-e^(-t/τ)), and En=

τ=(4x10^-6)(4000)=.016

Vfinial=17(1-e^(-.017/.016))=11.12v

En==2.473x10^-4J

1 the 4 is sig

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min