Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of magnitude B in the z-direction.
Find F, the magnitude of the magnetic force acting on the particle. Express your answer in terms of v, q, B, and other quantities given in the problem statement.

F = 0

Explanation:

This problem can be solved by using the equation for the force produced by a magnetic field over a charge

F = qv X B

That is, the cross product between velocity and the magnetic field.

In this case, v is in the negative z-direction v = -v k^,

and the magnetic field is in the positive z-direction B = z k^

Hence, the cross product is

F = qv X B = 0i^ - 0j^ + 0k^ = 0

In this case the net force is zero due to both velocity and magnetic field vectors are in the z-direction

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft