"A spaceship carrying a light clock moves at a speed of 0.960 c relative to an observer on Earth. If the clock on the ship advances by 1.00 s as measured by the space travelers aboard the ship, how long did that advance take as measured by the observer on Earth?"

Explanation:

Given :

Speed of ship

Time wrt. ship aboard sec

From the lorentz transformation,

Where improper time means time wrt. earth observer, proper time interval means time wrt. rest frame of ship observer.

And always improper time is grater than proper time which we call time dilation.

Put the values,

    ≅ 3.6 sec

Thus, the ship advance take 3.6 sec wrt. earth observer.

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explanation:

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