Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest. Red Car: 1000kg, 10m/s Yellow Car: 2,000kg, 5m/s Blue Car: 500kg, 20m/s Light Blue Car: 1,000kg, 20m/s Green Car: 500kg, 10m/s Purple Car: 4,000kg, 5m/s Part A Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them.

Ranking the cars based on magnitude of momentum (largest to smallest):

1. Purple, Light Blue

2. Red, Yellow, Blue

3. Green

Explanation:

Based on the given parameters ( mass and velocity), we can calculate the momentum of the various cars using the formula:

momentum = mass x velocity

1. Momentum of red car = 1000kg x 10m/s = 10,000Kgm/s

2. Momentum of Yellow car = 2000kg x 5m/s = 10,000Kgm/s

3. Momentum of blue car = 500kg x 20m/s = 10,000Kgm/s

4. Momentum of light blue car = 1000kg x 20m/s = 20,000Kgm/s

5. Momentum of green car = 500kg x 10m/s = 5,000Kgm/s

6. Momentum of purple car = 4000kg x 5m/s = 20,000Kgm/s

Hence,

Ranking the  based on magnitude of momentum (largest to smallest) we have:

1. Purple, Light Blue

2. Red, Yellow, Blue

3. Green

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s