We want to construct a solenoid with a resistance of 4.30 Ω and generate a magnetic field of 3.70 × 10−2 T at its center when applying 4.60 A of electrical current. We want to use copper wire with a diameter of 0.500 mm. If we need the solenoid's radius to be 1.00 cm, how many turns of wire will be need? 2 78 256 790 Then, what would be the required length of the solenoid? 12.3 cm

Answer with Explanation:

We are given that

Resistance of solenoid,R=4.3 ohm

Magnetic field,B=

Current,I=4.6 A

Diameter of wire,d=0.5 mm=

Radius of wire,r=

Radius of solenoid,r'=1 cm=

Resistivity of copper,

We know that

Where

Using the formula

Number of turns of wire=

Number of turns of wire=

Hence, the number of turns of the  solenoid,N=799

Magnetic field in solenoid,B=

Length of solenoid=12.5 cm

1m=100 cm

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2